2.8x^2-22x+6=0

Solution for 2.8x^2-22x+6=0 equation:

2.8x^2-22x+6=0

a = 2.8; b = -22; c = +6;
Δ = b2-4ac
Δ = -222-4·2.8·6
Δ = 416.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-\sqrt{416.8}}{2*2.8}=\frac{22-\sqrt{416.8}}{5.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+\sqrt{416.8}}{2*2.8}=\frac{22+\sqrt{416.8}}{5.6}
$